(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

This question is from the Nelson Grade 12 Physics textbook.

The force of attraction between massesmand_{1}mis 26N in magnitude. What will the magnitude of the force become if_{2}m_{2}

is tripled, and the distance betweenmand_{2}mis halved?_{1}

2. Relevant equations

F_{G}=(Gm_{1}m_{2})/r^{2}

G=6.67x10^{-11}

3. The attempt at a solution

I tried to look at both equations, the original and the altered equation so I had:

26N=(Gm_{1}m_{2})/r^{2}

and then for the changed equation I had"

F_{G}=(Gm_{1}3m_{2})/(1/2)(r^{2})

But I was unable to figure out what to do from there.

If it is at all helpful, the answers in the back of my textbook said that the correct answer is 3.1x10^{2}N.

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# Grade 12 Physics - Circular Motion - Universal Gravitation

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