Shortest collision time that will leave engine block intact?

In summary, the shortest collision time that will leave an engine block intact varies depending on factors such as speed, material, and angle of impact. While it is possible for an engine block to survive a high-speed collision, its resilience depends on the strength and durability of the material it is made of. There is no specific formula to calculate the shortest collision time for an intact engine block, as it is a complex process. During a collision, an engine block can deform or break under intense forces and pressure. It is possible to increase the collision survival rate of an engine block by reinforcing it with stronger materials, but this may affect its performance.
  • #1
kvkenyon
21
0

Homework Statement


In a crash test a solid concrete wall is
used to test crashworthiness. A particular
SUV weighs 338.183 kg and is accelerated to
33.3485 m/s before colliding head on with the
barrier.
What impulse must be applied is required
to stop the SUV?

This gives Impulse = 11277.896

The struggle comes with this part:

Through structural analysis of the SUV you
find out that 21801 N will destroy the engine
block. If we ignore the friction between the
car and the ground and assume the force the
wall exerts a constant force on the car, What
is the shortest collision time that will leave
the engine block intact?


Answer in units of s

Homework Equations



Impulse = net force * change in time

p(f) = p(i) + Impulse


The Attempt at a Solution



So I assumed that a force of 21800.9N force would mean that the engine
is not broken. I do not know if this assumption holds. However, it seems to make
sense in my mind. So i figured if the wall exerts a constant force of 11277.896N
causing the car to have a momentum of 0; the change in time is:

21800.9N/11277.896N --> 1.933064465s

But this is apparently wrong.
 
Physics news on Phys.org
  • #2
kvkenyon said:

Homework Statement


In a crash test a solid concrete wall is used to test crashworthiness. A particular SUV weighs 338.183 kg and is accelerated to 33.3485 m/s before colliding head on with the barrier.
What impulse must be applied is required to stop the SUV?

This gives Impulse = 11277.896 <---- units?

The struggle comes with this part:

Through structural analysis of the SUV you find out that 21801 N will destroy the engine
block. If we ignore the friction between the car and the ground and assume the force the
wall exerts a constant force on the car, What is the shortest collision time that will leave
the engine block intact?

Answer in units of s

Homework Equations



Impulse = net force * change in time

p(f) = p(i) + Impulse


The Attempt at a Solution



So I assumed that a force of 21800.9N force would mean that the engine is not broken. I do not know if this assumption holds. However, it seems to make sense in my mind.
Yes, you can take that to be the maximum allowable force.
So i figured if the wall exerts a constant force of 11277.896N causing the car to have a momentum of 0; the change in time is:

21800.9N/11277.896N --> 1.933064465s

But this is apparently wrong.
Look at the units. N divided by N yields a result without units, not seconds.

Consider your first Relevant Equation, then look at my comment in red above.
 
  • #3
I would also check 338.183 kg. It is much too little for an SUV. 3381.83 kg is more like it.
 
  • #4
So I see that my initial move was naive..haha

I rethought the problem. Right before impact my momentum will be 11277.896N.

If I don't want to destroy my motor I need to only contact the wall (If i could be so lucky to choose) for a very small amount of time so that my Impulse = 21000.9 N.

So I get, p(i) = 11277.896 N and I have to stop moving so my final momentum p(f) = 0.

so I get:

0 = 11277.896 + (-21800.9N)t

So if this logic is correct i just rearrange and get t. I made the force negative because it's acting in the opposite direction of motion.
 
  • #5
The kg is right...problem is clearly not realistic.
 
  • #6
Does this seems right at all? The system we use docks points off of our total score if we try and fail..So in the spirit of not trying because of fear of failure a little assurance would be great. In other words, if you say No that is wrong then I can go back to the drawing board, else I already did the work so it's ok for me to know it's right.
 
  • #7
Make sure that you carry correct units through your calculations. What are the units of momentum and impulse?

Your last version is fine (post #4), except you forgot to include the units on the impulse value. What value do you calculate for the time?
 
  • #8
Units of Impulse are kg*m/s --> N s; and momentum is N*s. Correct? and If the impulse value

11277.896N*s + (-21800.9N)t = 0 --> t = -11277.896N*s/-21800.9N = t (seconds)

(kg*m)/s * s*s/(kg*m) --> s

For some reason I believed that Force and Momentum had the same units...Now I see the error of my ways!

Thank you for the lending hand.

~Kevin
 
  • #9
.517 s --> Correct. Thanks again
 
  • #10
You're welcome :smile:
 

1. What is the shortest collision time that will leave an engine block intact?

The shortest collision time that will leave an engine block intact depends on various factors such as the speed of the collision, the material of the engine block, and the angle of impact. It is difficult to determine a specific time as it can vary greatly.

2. Can an engine block survive a high-speed collision?

It is possible for an engine block to survive a high-speed collision, but it largely depends on the strength and durability of the material it is made of. Some engine blocks are designed to withstand high impact forces, while others may not be as resilient.

3. Is there a formula to calculate the shortest collision time for an intact engine block?

There is no specific formula to calculate the shortest collision time that will leave an engine block intact. It is a complex process that involves various factors and is difficult to predict accurately.

4. What happens to an engine block during a collision?

During a collision, the engine block can experience intense forces and pressure, causing it to deform or break. The extent of the damage depends on the speed and angle of impact, as well as the strength of the engine block.

5. Can an engine block be reinforced to increase its collision survival rate?

Yes, engine blocks can be reinforced with stronger materials or design features to increase their collision survival rate. However, this may also add weight and affect the overall performance of the engine.

Similar threads

  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
5K
  • Introductory Physics Homework Help
2
Replies
63
Views
8K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
8
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
1K
Replies
14
Views
2K
  • Introductory Physics Homework Help
Replies
8
Views
4K
  • Introductory Physics Homework Help
Replies
5
Views
6K
Back
Top