Should You Switch? Solving the 3 Doors Problem

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Discussion Overview

The discussion revolves around the 3 Doors Problem, also known as the Monty Hall problem, and its implications in probability theory. Participants explore the nuances of probability based on the information provided about two families with children and how it relates to the game show scenario.

Discussion Character

  • Exploratory
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant suggests that both families (Red and Blue) have an equal probability of having a girl based on the initial information.
  • Another participant argues that given Red's oldest child is a boy, the probability of Red having a girl is 1 in 2, while Blue has a 2 in 3 chance of having a girl, thus Blue is more likely to have a girl.
  • A participant elaborates on the 3 Doors Problem, emphasizing that the outcome depends on whether the host knows where the prize is, which affects the probabilities of winning based on the decision to switch doors.
  • The same participant notes that if the host does not know where the prize is, the chances remain at 50%, but if the host does know, the chances of winning by sticking with the original choice drop to 33%.

Areas of Agreement / Disagreement

Participants express differing views on the probabilities associated with the families having girls, with no consensus reached. The discussion on the 3 Doors Problem also highlights competing interpretations regarding the host's knowledge and its impact on the probabilities.

Contextual Notes

The discussion includes assumptions about the host's knowledge in the 3 Doors Problem and the implications of the information provided about the families, which remain unresolved.

davee123
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Two new families move into your neighborhood. For the sake of argument, let's call one family Red, and the second family Blue. Each family has 2 children, whose genders you don't know. You're told that the Red's older child is a son. Then you ask the Blue parents if they have a son, to which they reply "yes". Which family is more likely to have a girl, and why?

DaveE
 
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From the given information both equally.
 
Given that Red's oldest is a boy, the only possible combinationsa re boy-boy or boy-girl, a 1 in 2 chance. For Blue, the possibilites are boy-girl or girl-boy or boy-boy, or a 2 in 3 chance, so Blue has the higher probability of having a girl.
 
daveb said:
so Blue has the higher probability of having a girl.
Ding! It's a question of what information the person who told you has access to, or had to examine in order to tell you what they knew. In the first case, the person who told you that Red's oldest child was a son didn't need to know the gender of the younger child to answer you. For blue, they had to know both genders in order to correctly answer.

It creates an interesting quirk with the 3 doors problem:

You're on a game show, with 3 prize doors, one of which has a prize, one of which doesn't. You randomly pick the 1st door. Now, before revealing what's in the 1st door, the host opens up door #2, and shows you that there's no prize there. He then gives you an opportunity to switch. Should you?

The twist is that the problem (as stated here) is incomplete. It's unanswerable unless we know whether or not the host knew where the prize was. If the host doesn't know where the prize is, we're still at a 50% chance of our door being correct. If they host DOES know where the prize is, we're at a 33% chance of our door being correct.

DaveE
 

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