Why does the limit of 1/x² not exist as x approaches zero?

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The limit of 1/x² as x approaches zero does not exist because it approaches infinity, which is not a real number. To prove this, one can assume the limit exists and then demonstrate that it cannot converge to any real number L. The limit indicates that for any large positive number M, there exists an interval around zero where 1/x² exceeds M. Therefore, since the limit diverges to infinity, it is classified as non-existent in the context of real numbers. The conclusion is that the limit does not exist due to its infinite nature.
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Homework Statement


Show limit 1/x^2 when x approaches zero does not exist.


Homework Equations





The Attempt at a Solution


What I do is suppose the limit exists,say L.Then I show that for all real number L, the limit does not approaches L. In this case, I separate L into different cases. Can anyone help me to check is this a valid prove.
 
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Yes, that is a valid approach.
 
\lim_{x \to 0}\frac{1}{x^2} = \infty

Since ∞ is not a real number the limit above is said not to exist. This limit means that for any large, positive number M, there is some interval around 0 such that if x is in that interval, 1/x2 > M.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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