Show set is a polygon connected set?

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SUMMARY

The discussion focuses on proving that the complement of the set S = {all (x, y) with x and y rational numbers} is a polygon connected set. The complement is defined as the set of all points (x, y) where either x or y is not rational. The user attempts to demonstrate this by considering various cases where x and y are irrational, using specific examples like (π, 2) and (e, 4) to illustrate the connection between points in the complement. The conclusion is that the complement forms a polygon connected set, but further proof is needed to solidify this claim.

PREREQUISITES
  • Understanding of rational and irrational numbers
  • Familiarity with polygon connectivity in topology
  • Basic knowledge of set theory and complements
  • Ability to visualize and construct geometric figures in a Cartesian plane
NEXT STEPS
  • Study the properties of polygon connected sets in topology
  • Learn about the concept of open sets in metric spaces
  • Explore proofs involving irrational numbers and their properties
  • Investigate the use of line segments in connecting points in a Cartesian plane
USEFUL FOR

Mathematics students, particularly those studying topology and set theory, as well as educators looking for examples of polygon connectivity and irrational number properties.

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Homework Statement



Show that the complement of the set S = {all (x, y) with x and y rational numbers} is a polygon connected set. Is it an open set?

Homework Equations





The Attempt at a Solution



The complement of S = {all (x, y) with x not rational or y not rational}
Let the points (x, y) and (z, w) exist in the complement of S.

Case 1:

Suppose x is not rational and z is not rational.

Case 2:

Suppose x is not rational and w is not rational.

Case 3:

Suppose y is not rational and z is not rational.

Case 4:

Suppose y is not rational and w is not rational.

I don't really know how to actually prove my four cases.
 
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Example: (pi,2) to (e,4)

Line segment from (pi,2) to (pi,pi), and another line segment from (pi,pi) to (e,pi), and finally another segment from (e,pi) to (e,4).
 

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