Show that f is a closed subset

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SUMMARY

The discussion centers on proving that the set of continuous functions, denoted as f = {g ∈ B(X) | g is continuous}, is a closed subset within the metric space (X, d). Participants clarify that a subset is closed if it contains all its boundary points. The proof involves demonstrating that if a sequence of bounded and continuous functions converges to a limit function f, then f must also be bounded and continuous, thereby confirming that f belongs to the set F. This conclusion establishes that F is indeed a closed subset.

PREREQUISITES
  • Understanding of metric spaces, specifically (X, d)
  • Knowledge of bounded functions and their properties
  • Familiarity with the definition of continuity in the context of metric spaces
  • Proficiency in the triangle inequality and its applications in analysis
NEXT STEPS
  • Study the properties of metric spaces and closed sets in topology
  • Learn about the convergence of sequences in function spaces
  • Explore the implications of the triangle inequality in proving continuity
  • Investigate the relationship between boundedness and continuity in functional analysis
USEFUL FOR

Mathematicians, students of analysis, and anyone interested in the properties of function spaces and topology will benefit from this discussion.

  • #31
MaxManus said:
I ment:
If {x_n} is a convergent sequence of elements in F, then the limit a =
lim x_n always belongs to F. = F is closed. I thought you used this rule, but no?

That's what you just did. Translate the statement '(blank) is an element of F' to '(blank) is continuous and bounded' where (blank) is anything. Because that's the definition of F!
 
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  • #32
Thanks for your patience. It took some days, but I get that the two are the same thing now.
 

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