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Show that the Ʃ 1/(2n-1)^3 Converges

  1. Dec 3, 2011 #1
    1. The problem statement, all variables and given/known data

    Show that the Ʃ 1/(2n-1)^3 Converges


    3. The attempt at a solution

    I tried using the ratio the ratio test but that didn't work
     
  2. jcsd
  3. Dec 3, 2011 #2

    Curious3141

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    I assume the summation is over all non-negative n (i.e. 1,2,3..)?

    Just compare with zeta(3) (which has all positive terms and includes all the terms in your series), which converges. If you need to establish convergence of the latter, use the integral test, i.e. prove that ∫x^(-n)dx for the bounds [1, infinity) is finite for all n > 1 (here the n is 3).

    EDIT: Damn Latex :grumpy:
     
    Last edited: Dec 3, 2011
  4. Dec 3, 2011 #3

    Dick

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    Good advice, but it's probably clearer if you say summation 1/n^3 instead of zeta(3). Not everybody knows the Riemann zeta function.
     
  5. Dec 3, 2011 #4

    Curious3141

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    Fair enough.:smile:
     
  6. Dec 3, 2011 #5
    If I say 1/n^3 could I also use the p-series test.

    and yes i meant the summation where n=1 to infinity
     
  7. Dec 4, 2011 #6

    Curious3141

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    If you're allowed to assume the p-series convergence for p = 3, that's essentially the same thing as assuming the convergence for zeta(3). Then you don't even need the integral test. Just compare and you're done.
     
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