Show that x(t) approaches infinity in finite time

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Homework Help Overview

The discussion revolves around the differential equation \(\dot{x} = rx + x^3\), where \(r > 0\) is a constant. Participants are tasked with showing that \(x(t)\) approaches infinity in finite time from any initial condition \(x_0 \neq 0\).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the implications of \(x(t)\) approaching infinity in finite time, questioning the meaning of this behavior. There are attempts to solve the equation through integration and discussions about the physical interpretation of the solution.

Discussion Status

The conversation includes various attempts to manipulate the equation and integrate it, with some participants expressing uncertainty about the physical meaning of the results. There is acknowledgment of potential asymptotic behavior, but no consensus on the interpretation or the physical model.

Contextual Notes

Some participants express confusion about the mathematical steps involved, particularly regarding partial fraction decomposition and the implications of the solution. There is a mention of a constant of integration and its relevance to the problem.

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Homework Statement



Consider the equation \dot{x} = rx + x^3, where r>0 is fixed. Show that x(t) \rightarrow \pm \infty in finite time, starting from any initial condition x_{0} \neq 0.

Homework Equations



I can think of none.

The Attempt at a Solution



The idea alone of x(t) approaching infinity in "finite time" throws me for a loop. Does this merely mean that |x(t)| becomes very large very quickly? That it is increasing (x > 0) or decreasing (x < 0) increasingly quickly as it "moves away from the origin"? It strikes me as impossible for something to "become infinite" in a finite amount of time. This is from Strogatz' "Nonlinear Dynamics and Chaos", Exercise 2.5.3 if you are interested.

Thank you!
 
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Solve the equation! You have:
<br /> \frac{1}{x(r+x^{2})}\frac{dx}{dt}=1<br />
Use partial fractions to separate to get:
<br /> \frac{1}{x(r+x^{2})}=\frac{1}{rx}-\frac{1}{r(r+x^{2})}<br />
And then simply integrate, this will give the answer.
 
I would assume the phrase "approaches infinity in finite time" means the graph has an asymptote.
 
Indeed. There is a vertical asymptote as a certain finite value of t.
 
I think I now understand the math behind this, although I'm unable to come up with a physical situation that models it?
 
First off, can you do the integral?
<br /> \frac{1}{r}\int \frac{1}{x}-\frac{1}{r+x^{2}}dx=\int 1dt<br />
Physically this would represent a shock wave of some kind.
 
We end up with: \frac{ln(x) - (\arctan(x/\sqrt{r})/\sqrt{r})}{4} = t. So if this is a shockwave, what exactly is x(t) modeling? Surely not position?

Sorry for what I can kind of tell are pretty basic questions. I've had very little experience with differential equations so I'm sort of learning as I go along in Strogatz.
 
Last edited:
You also have a constant of integration in there somewhere which you can calculate.

x would represent something like the gradient of the wave at a given time.

So what values on the RHS would make it infinite? look at both the log and arctan terms.
 
Are you sure about that partial fraction simplification? I get
\frac{1}{rx} - \frac{x}{r(r+x^2)}
 
  • #10
I think you could be right there...
 

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