A charged particle drifts in uniform, constant magnetic and electric fields. The electric field, E, is perpendicular to the magnetic field, B. Show that the drift velocity is given by vd = (E×B)/B2 Heres where I get to: F=e(E+vxB)=0 as v is uniform. Therefore E+vxB=0. Take vector product of B with both sides. BxE +Bx(vxB)=0. Using identity Ax(BxC) = B(A.C)-C(A.B) I get BxE+v(B.B)-B(B.v)=0 Then I don't know where to go from here.