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shedrick94
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HW Template missing as it was moved from another forum
A charged particle drifts in uniform, constant magnetic and electric fields. The electric field, E, is perpendicular to the magnetic field, B.
Show that the drift velocity is given by vd = (E×B)/B2
Heres where I get to:
F=e(E+vxB)=0 as v is uniform.Therefore E+vxB=0.
Take vector product of B with both sides.
BxE +Bx(vxB)=0.
Using identity Ax(BxC) = B(A.C)-C(A.B)
I get BxE+v(B.B)-B(B.v)=0
Then I don't know where to go from here.
Show that the drift velocity is given by vd = (E×B)/B2
Heres where I get to:
F=e(E+vxB)=0 as v is uniform.Therefore E+vxB=0.
Take vector product of B with both sides.
BxE +Bx(vxB)=0.
Using identity Ax(BxC) = B(A.C)-C(A.B)
I get BxE+v(B.B)-B(B.v)=0
Then I don't know where to go from here.