Show ZXZ is an infinite cyclic group.

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SUMMARY

ZXZ is confirmed as an infinite cyclic group under addition. The group is generated by the set of vectors {(1,0), (0,1)}, which allows for the generation of all elements in ZXZ. Initially, there was confusion regarding the generation of elements like (2,3), but it was clarified that multiple generators are necessary to span the entire group. This discussion highlights the importance of understanding the structure of infinite cyclic groups in group theory.

PREREQUISITES
  • Understanding of group theory concepts, specifically cyclic groups.
  • Familiarity with vector spaces and their generation.
  • Knowledge of the integers and their properties under addition.
  • Basic proficiency in mathematical notation and terminology.
NEXT STEPS
  • Study the properties of infinite cyclic groups in more depth.
  • Learn about generating sets in vector spaces.
  • Explore the relationship between generators and group structure.
  • Investigate examples of other infinite groups and their generators.
USEFUL FOR

This discussion is beneficial for students of abstract algebra, mathematicians studying group theory, and educators teaching concepts related to cyclic groups and vector spaces.

Daveyboy
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Homework Statement



Show ZXZ is an infinite cyclic group. Under addition of course.

Homework Equations


The Attempt at a Solution


So this obviously is an infinite cyclic group. Z is generated by <1> or <-1>.
The problem I run into here is I think <(1,1)> will only generate elements of the form (a,a) s.t. a is an element of Z, (think along the diagonal). I do not see a way to generate something like (2,3).
 
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Wow, sorry I was confused, I see that there can not be any generators of ZXZ.
 
There can be generators. You just need more than one to generate the group. E.g. {(1,0), (0,1)} is a set that generates the whole group.
 

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