Showing that a function is in [itex]L^2(\mathbb{R}^2)[/itex]

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lmedin02
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Homework Statement


Suppose [itex]f\in L^2(\mathbb{R}^2)[/itex]. Is [itex]f+c\in L^2(\mathbb{R}^2)[/itex] where c is a constant?

Homework Equations


[itex]f\in L^2(\mathbb{R}^2)[/itex] if [itex]||f||_2<∞[/itex].


The Attempt at a Solution


I think the answer is no because [itex]∫_{\mathbb{R}^2}{c^2}dx=∞[/itex]. However, I am still unsure. Any guidance is appreciated.
 
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lmedin02 said:

Homework Statement


Suppose [itex]f\in L^2(\mathbb{R}^2)[/itex]. Is [itex]f+c\in L^2(\mathbb{R}^2)[/itex] where c is a constant?

Homework Equations


[itex]f\in L^2(\mathbb{R}^2)[/itex] if [itex]||f||_2<∞[/itex].


The Attempt at a Solution


I think the answer is no because [itex]∫_{\mathbb{R}^2}{c^2}dx=∞[/itex]. However, I am still unsure. Any guidance is appreciated.
You are correct. For a simple counterexample, take ##f(x) = 0## for all ##x##. Then ##f \in L^2##, but if ##c## is any nonzero constant, then ##f + c \not\in L^2##, for the reason you indicated.