Showing that KE is minimized when objects stick together in a collision

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SUMMARY

This discussion focuses on demonstrating that kinetic energy (KE) is minimized in an inelastic collision when two objects stick together. The kinetic energy equation provided is K_f = 1/2 m_A (V_Ax^2 + V_Ay^2) + 1/2 m_B (V_Bx^2 + V_By^2). The steps outlined include taking derivatives of velocity variables, applying momentum conservation principles, and analyzing concavity through second derivatives to confirm that the minimum KE occurs when the objects are combined post-collision.

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  • Understanding of inelastic collisions
  • Familiarity with kinetic energy equations
  • Knowledge of momentum conservation principles
  • Basic calculus, including derivatives and concavity analysis
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  • Study the principles of inelastic collisions in physics
  • Learn about kinetic energy and its mathematical representation
  • Explore momentum conservation in both x and y directions
  • Review calculus techniques for taking derivatives and analyzing concavity
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Students studying physics, particularly those focusing on mechanics and collisions, as well as educators seeking to explain the principles of kinetic energy minimization in inelastic collisions.

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Homework Statement



This problem deals with an inelastic collision, where Mass A is given an initial velocity and collides with Mass B which is initially at rest.

The equation I'm given is

[itex]K_f = \frac{1}{2} m_A (V_Ax^2 + V_Ay^2) + \frac{1}{2} m_B (V_Bx^2 + V_By^2)[/itex]
The x's and y's are part of the subscript.

So the problem says:

Start with the expression shown above for the system's kinetic energy after the collision. Energy is not a vector, but the final total speeds are expressed with x and y components, by Pythagorean theorem. This notation puts them on a comparable footing with momentum, which is a vector.

Show that this quantity is minimized when the objects stick together.

The following steps will walk you through it:

a) Take the derivative with respect to anyone of the four velocity variables (your choice).

b) The x and y directions are independent, i.e. if you pick an x variable, the derivatives of the y variables are 0.

c) The two variables along the same axis are NOT independent. Use momentum to make a substitution. This should lead to some clear conclusions.

d) Now take the 2nd derivative to get the concavity. What sign should it be?

e) Without recomputing, extrapolate what you would have gotten if you had chosen a variable from the other axis in step a (y instead of x, etc.). Why is this step necessary to demonstrate that the objects truly do "stick together"? The attempt at a solution

So for part a, I chose to take the derivative with respect to Vax and I get
dk/dVa = [itex]m_A V_A + m_B V_B (dV_B/dV_A)[/itex]

Now I'm really lost on part c. I'm really unclear as to how to use momentum and what to substitute in.
 
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Azu_ said:
I'm really unclear as to how to use momentum and what to substitute in.
Momentum is a conserved vector, so it is conserved in each of the directions, x and y, separately. Write down two equations expressing this.
 

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