Showing that the Schrödinger equation implies the de Broglie relation when PE=0

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
3 replies · 2K views
qLinusq
Messages
2
Reaction score
0
Hello,

In the book physical chemistry (P. Atkins & Julio de Paula, 2009, 5 ED) the authors derive a justification of the Schrödinger equation.

1.) [tex]\frac{-\hbar^{2}}{2m} \frac{d^{2}\psi}{dx^{2}}+V(x)\psi=E \psi[/tex]

The derivation goes as follows:

Derivation:
We can justify the form of the Schrödinger equation to a certain extent by showing that it implies the de Broglie relation for a freely moving particle.
By free motion we mean motion in a region where the potential energy is zero (V=0 everywhere).

If V=0, equation 1 simplifies to:

2.) [tex]\frac{-\hbar^{2}}{2m} \frac{d^{2}\psi}{dx^{2}}=E \psi[/tex]

So far all good, however they then present a solution to equation 2. without showing how they obtained it.

The solution is:

[tex]\psi=sin(kx)[/tex]
[tex]k=\frac{(2mE)^{2}}{\hbar}[/tex]

I have no problem understanding that this is a valid solution however i would like to derive it myself.

Could you provide me with the derivation to the solution of equation 2?

/Thanks in advance,

Linus.
 
Physics news on Phys.org
qLinusq said:
Could you provide me with the derivation to the solution of equation 2?

I think you can find it here:

http://www.cliffsnotes.com/study_guide/Constant-Coefficients.topicArticleId-19736,articleId-19720.html
 
Last edited by a moderator:
qLinusq said:
i would like to derive it myself.

Could you provide me with the derivation to the solution of equation 2?

:confused: :smile:
 
Lol, yes I can see how what I wrote is contradicting. That is the kind of help that I was looking for actually.

/Thank you torquil :)