Showing the solution of an Euler DE oscillates

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SUMMARY

The discussion focuses on the oscillatory behavior of solutions to an Euler differential equation (DE) when the parameter k exceeds 1/4. It is established that for k > 1/4, the roots of the indicial equation become complex, leading to solutions that incorporate trigonometric functions, specifically cos(x) and sin(x), which are inherently oscillatory. Conversely, when k ≤ 1/4, the solutions do not exhibit oscillation. The mathematical derivation involves the quadratic formula, revealing the conditions under which the roots are complex.

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  • Understanding of Euler differential equations
  • Familiarity with complex numbers and their properties
  • Knowledge of the quadratic formula
  • Basic concepts of oscillatory functions (sine and cosine)
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  • Study the derivation of the indicial equation for Euler DEs
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Homework Statement


I have the DE
gif.latex?y%5E%7B%27%27%7D%20+%20%5Cfrac%7Bk%7D%7Bx%5E%7B2%7D%7D%20y%20%3D0.gif
which is an Euler DE. Show that if k >1/4, the solution of the DE would oscillate.

Homework Equations


eix= cos(x) +isin(x) I assume.

The Attempt at a Solution


I understand here that if k>1/4 the solution of the DE may oscillate, but if k
gif.gif
1/4, it will not. I understand why it would oscillate because the roots of the indicial equation would come on out as complex because if you were to plug the values into the quadratic formula, you would receive a negative under the square root. Other than explaining it in this fashion, how would some one show this though?

Here I have r=[-1 +/- sqrt(1-4k)]/2
 
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Well if you have an imaginary characteristic root, then the solution contains cos(x) and sin(x) which would be oscillatory. If you want find the actual solutions in terms of k (assuming k > 1/4).
 

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