Showing Two Functions Are Symmetric About A Line

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Homework Help Overview

The discussion revolves around demonstrating the symmetry of two functions, \( y_1 = \frac{c}{b} + d e^{-bx} \) and \( y_2 = \frac{c}{b} - d e^{-bx} \), about the line \( y = \frac{c}{d} \). Participants are exploring the mathematical properties and implications of symmetry in this context.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster considers using distance formulas to show symmetry and questions the validity of this approach. Other participants suggest that the distance should not involve \( x \) and propose that the distances between specific points should be equal. There is also mention of a potentially simpler method to demonstrate symmetry.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions about the distance calculations and exploring alternative methods. Some guidance has been offered regarding the distance formula, and there is an ongoing inquiry into the nature of the functions and their graphical representations.

Contextual Notes

There are indications of confusion regarding the correct expressions and assumptions about the functions, as well as the implications of their graphical representations. Participants are navigating these complexities without reaching a definitive conclusion.

Bashyboy
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Hello everyone,

I have the functions [itex]y_1 = \frac{c}{b} + d e^{-bx}[/itex] and[itex]y_2 = \frac{c}{b} - d e^{-bx}[/itex], where [itex]c \in \mathbb{R}[/itex], and [itex]b,d \in \mathbb{R}^+[/itex].
What I would like to know is how to show that these two functions are symmetric about the line [itex]y = \frac{c}{d}[/itex].

What I thought was that if y_1 and y_2 are symmetric about the line [itex]y = \frac{c}{d}[/itex], then the distance between y_1 and y, and the distance between y_2 and y, will be the same. That is, [itex]d_1 = \sqrt{(y_1 - y)^2 + (x - x_0)^2}[/itex] and [itex]d_2 = \sqrt{(y_2 - y)^2 + (x - x_0)^2}[/itex], where [itex]d_1 = d_2[/itex].

Is this a correct way of determining symmetry? Is it true in general? Are there any other ways in which I could prove symmetry?
 
Last edited:
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Bashyboy said:
Hello everyone,

I have the functions [itex]y_1 = \frac{c}{b} + d e^{-bx}[/itex] and[itex]y_2 = \frac{c}{b} - d e^{-bx}[/itex], where [itex]c \in \mathbb{R}[/itex], and [itex]b,d \in \mathbb{R}[/itex].
What I would like to know is how to show that these two functions are symmetric about the line [itex]y = \frac{c}{d}[/itex].

What I thought was that if y_1 and y_2 are symmetric about the line [itex]y = \frac{c}{d}[/itex], then the distance between y_1 and y, and the distance between y_2 and y, will be the same. That is, [itex]d_1 = \sqrt{(y_1 - y)^2 + (x - x_0)^2}[/itex] and [itex]d_2 = \sqrt{(y_2 - y)^2 + (x - x_0)^2}[/itex], where [itex]d_1 = d_2[/itex].

Is this a correct way of determining symmetry? Is it true in general? Are there any other ways in which I could prove symmetry?

Some comments:

(1) Your distance formula should not involve x, because for each x separately you want to show that the distance between the points (x,c/b) and (x,y_1(x)) is the same as the distance between the points (x,c/b) and (x,y_2(x)). The x drops out of these distance formulas (although, of course, they still contain y_1(x) and y_2(x)). After that, what you say would be correct.

(2) There is a much easier way.
 
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And what might this easier method be, Ray?
 
Bashyboy said:
And what might this easier method be, Ray?

That is for you to think about; I am not allowed to give solutions, nor would I want to. I can make one suggestion, however: think about what you would get if you drew graphs of the two functions on the same plot.
 
I have already drawn the plot of these functions, and that was how I made inference I made, that the distances must be the same. I am not sure what else could be concluded from the plots.
 
Would it perhaps be that the sum of the functions y1 and y2 is identically zero for all x, where is a real number?
 
Bashyboy said:
Would it perhaps be that the sum of the functions y1 and y2 is identically zero for all x, where is a real number?

Well, how would you write it after correcting your erroneous expressions given before?
 

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