Showing two matrices are not unitarily similar

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Matrices A and B are shown to be not unitarily similar by examining their properties. A is defined as |1 2| |0 3| and B as |1 0| |0 3|. The argument hinges on the fact that if B were unitarily similar to A, then A would also have to be symmetric, which it is not. Additionally, the columns of B are orthogonal, while those of A are not, reinforcing their dissimilarity. Thus, A and B cannot be unitarily equivalent due to these fundamental differences in their properties.
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Let A=
|1 2|
|0 3|
and B=
|1 0|
|0 3|
Show that A and B are not unitarily similar?
 
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anyone have an idea of how to do this?
 
if B = UAU^-1 = UAU* (where U is unitary), then

B* = (UAU*)* = (U*)*A*U* = UA*U*.

but B is symmetric so B = B*. hence we would have

UAU* = UA*U*, and so

U*UAU*U = U*UA*U*U and

A = A*, implying A is symmetric as well, which is false.
 
The same thing said in another way: The columns of B are orthogonal, unitary transformation preserves orthogonality, but the columns of A are not orthogonal. Therefore A and B are not unitarily equivalent.
 
indeed, it all depends on how you define "unitary", by inner product properties, or matrix properties. there is a deep connection betwen inner products and matrix multiplication.
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

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