Sig Figs in Physics Problems: Explanation for Two Calculations

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The discussion focuses on determining the number of significant figures (sig figs) to retain in two specific physics calculations. For the first calculation, 12.00000 x 0.9893 + 13.00335 x 0.0107, the result should retain three significant figures due to the multiplication involving the least number of sig figs. In the second calculation, (11.13-2.6) x 10^4 / (103.05 + 16.9) x 10^-6, the subtraction yields 8.5, which has two significant figures, thus influencing the overall result. The importance of proper uncertainty analysis is also noted, emphasizing that significant figures are a guideline rather than a comprehensive measure. Understanding these rules is essential for accurate scientific calculations.
p4cifico
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I need an explanation for these two problems

How many sig figs should be retained in the result of the following calculation?

12.00000 x 0.9893 + 13.00335 x 0.0107

and

(11.13-2.6) x 10^4 / (103.05 + 16.9) x 10 ^-6
 
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3 and 2.

Significant fig's is just a rule of thumb, proper uncertainty analysis is more detailed.
 
Last edited:
p4cifico said:
I need an explanation for these two problems

How many sig figs should be retained in the result of the following calculation?

12.00000 x 0.9893 + 13.00335 x 0.0107

and

(11.13-2.6) x 10^4 / (103.05 + 16.9) x 10 ^-6
Pick the number in multiplication or division with the least number of SF.
In your first eq., it is 3.
In your second, you first have to do 11.13-2.6=8.5, with 2 SF.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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