Sigma Algebra on Omega (Sample Space)

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SUMMARY

The discussion centers on the sigma algebra related to the sample space Ω of three coin tosses, specifically F_0 and F_1. F_0 is defined as {∅, Ω}, while F_1 includes {∅, Ω, A_H, A_T}, where A_H and A_T represent the outcomes based on the first coin toss. The proof presented indicates that the intersection of F_0 and F_1 results in F_0, which only contains the empty set and the entire sample space. The confusion arises regarding why A_H and A_T are not included in the intersection, as they do not meet the criteria for membership in F_0.

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woundedtiger4
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Respected Members,

Suppose Ω is the set of eight possible outcomes of three coin tosses i.e. Ω={{HHH, HHT, HTH, HTTT, THH, THT, TTH, TTT}
So if we are not told the results then the sigma algebra ( denoted by F_α) at position α=0 is
F_0 = {∅, Ω}

Now if are told the first coin toss only then,
A_H={HHH, HHT, HTH, HTTT}, and A_T={THH, THT, TTH, TTT}
which the sigma Algebra at α=1 is
F_1={∅, Ω, A_H, A_T}

now in the attached picture the proof says that

A_1, A_2,..., A_n,... ε ∩_αεI F

if we just consider two sigma algebras for our convenience to check this let's take the intersection of two above coin toss's sigma algebras i.e. F_0 and F_1

for I= 0 and 1,

∩_αεI F_α = F_0 ∩ F_1 = {∅, Ω} ∩ {∅, Ω, A_H, A_T} = {∅, Ω} ----(BETA)

the proof says that A_1, A_2,..., A_n,... ε ∩_αεI F_α , and if we consider A_1 as A_H and A_2 as A_T then why are they not in the intersection of F_0 ∩ F_1 as shown in (BETA) ?

Thanks in advance.
 
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You have \mathcal F_0=\{\emptyset,\Omega\} and \mathcal F_1=\{\emptyset,A_H,A_T\Omega\}. In particular, since \mathcal F_0\subseteq \mathcal F_1, your example has \mathcal F_0\cap\mathcal F_1=\mathcal F_0.

What you need for your hypothesis is A_i \in \mathcal F_0\cap\mathcal F_1=\mathcal F_0=\{\emptyset,\Omega\} for every i. That is, every A_i is either empty or the whole state space; in particular, you can't use A_i=A_H or A_i=A_T. To verify the union, notice that the union is just \Omega if at least one of your A_i=\Omega and \emptyset if (the only other possibility) every A_i=\emptyset. In particular, either way, \bigcup_i A_i \in \mathcal F_0.
 
Why not A_i=A_H or A_T ? Let's say, A_1={ø}, A_2={Omega}, A_3=A_H and A_4=A_T then A_1, A_2, A_3, A_4 belongs to intersection_alpha belongs to I F_alpha, here F_alpha is F_0
After all A_H and A_T are the subsets of Omega, and definition 7 says that algebra is a collection of subsets of Omega.

Ps. Sorry, I am on train and typing this message on mobile therefore I am unable to add accurate symbols :(
 

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