Simple AC circuit theory problem

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SUMMARY

The discussion focuses on solving a simple AC circuit problem involving a 100-ohm resistor and a 10mH inductor in series, with a voltage function of V = 20sin(5000t). The peak current is determined using the formula I = V/Z, where Z is the impedance calculated as Z = sqrt(R² + XL²). The inductive reactance (XL) is calculated using the frequency derived from the given voltage function, confirming that integration is not necessary for this specific problem.

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  • Understanding of AC circuit theory
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  • Knowledge of inductive reactance (XL) and its formula
  • Ability to work with sinusoidal voltage functions
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  • Study the concept of impedance in AC circuits
  • Explore the application of phasors in AC circuit analysis
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Homework Statement



It's a simple AC circuit with a 100ohm resistor and a 10mH inductor connected in series. The voltage is given as a function rather than a quantity: V = 20sin (5000t).

Problem asks to find the peak current in the circuit.

Homework Equations



i = integral (V/L)dt
Z = sqrt (R2 + XL2
V=IZ

The Attempt at a Solution



Is it as simple as saying the peak voltage is 20V and the frequency is f = 5000/2pi , and then solving it like a normal AC circuit? Or is any integration required, or anything similar? I am quite clueless, any help would be appreciated thanks :)
 
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Welcome to PF.

Looks like you are on the right track, assuming you know how to calculate XL for the inductor.
 
thanks I've got it... I = V/Z... z= r+j(wl).. just didnt realize it's that simple.
 

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