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**[SOLVED] Simple Acceleration Equation Help**

g=-9.80 m/s^2

t= 3.85

vi= 0.00 m/s

d=?

d=vi(t) + (1/2)gt^2

d=0 + (1/2)(-9.80m/s^2)((3.85s)^2)

=-72.6

I'm trying to find the distance. So, this d represents displacement. Since in this case, this is also the distance, would there be any other work to show the sign change, since the d would be going from a vector to a scalar? Or should I have modified this equation beforehand to show d as a scalar, and not have taken into account the gravities negative?

By the way, sorry, this must seem like a trivial matter really not worth time, but I hate not understanding it down to the tiny details. Thank you very much!