Simple but difficult for me. momentum, collsion

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SUMMARY

The problem involves two identical bodies colliding on a frictionless surface, with one moving at 1 m/s and the other at 2 m/s. The correct approach to find the magnitude of the velocity of the combined mass after the collision is to use the conservation of momentum formula: p1 = m1(v1f - v1i) + m2(v2f - v2i) = vf(m1 + m2). The correct answer is 2/3 m/s, which corresponds to option B. The initial incorrect calculations stemmed from misunderstanding the application of momentum conservation in inelastic collisions.

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Homework Statement



Two identical bodies are sliding toward each other on a frictionless surface. One moves at 1 m/s and the other at 2 m/s. They collide and stick. The magnitude of the velocity of the combined mass is
A. 3/4 m/s.
B. 2/3 m/s.
C. 1/6 m/s.
D. 1/2 m/s.
E. 1.5 m/s.
F. none of these

Homework Equations



p1=m1(v1f-v1i)+m2(v2f-v2i)=vf(m1+m2) i think that's right. {(?))

The Attempt at a Solution



ohkay, so using the idea behind the equation i just wrote.. i did

m's are irrelevant since theyre the same

so 1m/s + 2m/s = 3m/s
so at first thought i say okay its 3/3, so 1, that's not an option, so i picked F. Wrong.

then i did m(1) +m(2) = vf (m+m)

i picked 3/2, maybe the velocity over 2 masses? so 3/2=1.5m/s

Wrong. what the heck am i doing wrong, can anyone tell me how to approach a situation like this?
 
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hello everyone, please excuse this, as i accidentally posted it twice =X
 

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