Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Simple Circuits

  1. Jan 18, 2017 #1
    Assuming the resistance of a wire in a series circuit, consisting only of 1 component (e.g. filament lamp) and a battery, is negligible; does each Coulomb of charge commit all of its electrical potential energy, supplied by the battery's potential difference, as work done across the component (thus electrical potential energy gained at battery = electrical potential energy lost across component)?

    If so, how is voltage divided evenly across 2 identical components in series?
    i.e. how do the circuit electrons give up only half their electrical potential energy at component 1, to 'save' some electrical potential energy for component 2?
     
    Last edited by a moderator: Jan 18, 2017
  2. jcsd
  3. Jan 18, 2017 #2

    Drakkith

    User Avatar

    Staff: Mentor

    Ideally, yes. In real circuits some is lost in the wire and in the battery.

    Remember that electrons do not exist by themselves in a circuit, but as a collection of a great many electrons. The battery does work on the entire circuit, including all of the electrons, all at once. So if you look at electron A, you cannot say that it has 10 volts of electric potential energy, of which it gives half to resistor 1 and half to resistor 2. Instead you have trillions of electrons whose collective behavior delivers the energy to each component in the circuit.

    In fact, the motion of each electron is completely random, and the battery only causes a small net motion in a certain direction. This slight imbalance between directions is what gives rise to the movement of charge through the circuit. If you could look at a single slice of the circuit, you would see electrons crossing it from both directions, with one direction having slightly more electrons over time.
     
  4. Jan 19, 2017 #3

    jim hardy

    User Avatar
    Science Advisor
    Gold Member
    2016 Award


    When starting out it's difficult to work these conundrums in your head.
    Use your everyday experience on them.
    As a kid, did you ever slide down a not very steep, slow sliding board made for little guys and feel it warm the seat of your pants ? Halfway down you've converted half your potential energy into heating your backside.

    Any help ?

    old jim
     
  5. Jan 19, 2017 #4

    davenn

    User Avatar
    Science Advisor
    Gold Member

    lets look at a couple of examples

    upload_2017-1-20_7-44-43.png

    The left hand part just shows a single resistor across the 10V power supply
    Using Ohms Law, we can work out the total current flowing in the circuit

    I = V / R ( Current = Voltage / Resistance)
    I = 10V / 30 Ohms
    I = 0.33 Amps

    in the second circuit if we want to find the voltage drop across each resistor
    We first do that same step again work out the total current flowing in the circuit

    I = V / R
    I = 10V / 60 Ohms ( 30 Ohms + 30 Ohms)
    I = 0.166

    Now that we know the total current flowing, we can now use Ohms Law rearranged to find the voltage drop across each resistor
    NOTE ... because the resistors are the same value, the voltage drop will be the same across each of them ... therefor we only need to work out the voltage drop across one of the resistors

    V = I x R
    V = 0.166 x 30
    V = 4.98V

    Close enough to 5V drop across each resistor

    Now you could do an example where the two resistors are different values and work out the voltage drop across
    each resistor.
    NOTE .. the addition of the 2 voltage drops will always equal the total voltage across the circuit.


    Dave
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Simple Circuits
  1. Simple Circuit (Replies: 1)

  2. Simple Diode Circuits (Replies: 2)

  3. Simple magnet circuit (Replies: 0)

Loading...