This isn't a hwk question, it's just something I've been trying to show my dad. I'm probably wrong. Okay my question is, suppose you pick ONE letter out of the alphabet. The odds of me picking your letter are 1/26, if I only have one guess. However, if I have two guesses, aren't the odds a LITTLE bit more than 2/26? The reason why I think so is if you do the calculation this way: Find out what the prob. is that you DONT pick the letter. Then it is (25/26)*(24/26). Since there are 25 ways to pick the wrong first letter, and then 24 ways to pick the wrong letter a second time. Now you just do 1 minus the above to get the probability it is that you pick the CORRECT letter. Is my reasoning right? Also, obviously, if this is true, you can then extend it to three guesses, and four, etc. by: 25*24*23*22*.../26^(n) where 'n' is how many tries you took. Thanks!