Simple Constant acceleration equation but I dont get it!

  • Thread starter FireWarden
  • Start date
  • #1
FireWarden
4
0

Homework Statement



A particle moving at 5 m/s reverses its direction in 1s to move at 5 m/s in the opposite direction. If is acceleration is constant, what distance does it travel?


Homework Equations


The constant acceleration equations

The Attempt at a Solution


I use x=vot + 1/2at2 were a= (vfinal- vinitial)/t. I get the wrong answer. Something about having to plug in half the time for some reason that I don't understand. Would some one please help me out?
 

Answers and Replies

  • #2
kuruman
Science Advisor
Homework Helper
Insights Author
Gold Member
2021 Award
12,025
5,058
I get the wrong answer.

Can you show us what answer you got and how?
 
  • #3
FireWarden
4
0
I get get the answer to be distance equals 0 because i use:

vi to be 5 m/s
vf to be -5m/s
a to be -10

I plug those in to the equations mentioned above. It seems to be the incorrect answer but doesn't it make sense? I must be missing fundamental here.
 
  • #4
kuruman
Science Advisor
Homework Helper
Insights Author
Gold Member
2021 Award
12,025
5,058
You have correctly found zero which is the displacement. However the problem is asking to find the distance. Distance is not the same as displacement. Imagine an odometer hooked up to the particle. By how much has the odometer changed when the particle has gone out and come back to where it started?
 
  • #5
FireWarden
4
0
I got it. Thanks.

Much much karma to you.
 

Suggested for: Simple Constant acceleration equation but I dont get it!

Replies
8
Views
242
Replies
4
Views
213
Replies
5
Views
445
  • Last Post
Replies
4
Views
657
Replies
28
Views
735
Replies
29
Views
425
Replies
11
Views
441
Replies
4
Views
434
Top