Simple cosine expression NOT so simple

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SUMMARY

The discussion centers on the integration of the expression f(x) = Sqrt(1 + kcos(x)), specifically to find the area under the curve between x=0 and x=π. Participants concluded that the integral does not have a solution in terms of elementary functions and is classified as an elliptic integral. The use of Wolfram Alpha's integrator was highlighted as a valuable resource for solving such complex integrals. The conversation emphasizes the challenges of integrating functions involving square roots and trigonometric components.

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Mark Wood
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I am rediscovering my long lost "A" level maths and have been having lots of fun working on puzzles. Unfortunately, I seem to have hit something of a wall in the following simple expression that is repelling every attack I launch:

f(x)=Sqrt(1+kcos(x))

I have tried substituting x=arccos(w) and w=arccos(w/k), expressing things as logs, mungeing the equations I get, and a number of slightly more desperate attacks, but whatever I do to get rid of one term or provide something that can be canceled out, a new problem pops up.

I feel that there is a simple answer to this, but the more I look at it the less I can see the way forward.

Any suggestions anyone?
 
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What exactly do you want to do with f(x)?
 
Ah! So absorbed by it, I've missed the most important bit!

I'm trying to integrate it to get the area under the curve between x=0 and x=pi
 
Sorry, i couldn't get ur expression. is it (1+kcos(x))^(1/2)
 
Yes it is - the root of (1+kcos(x))
 
I don't think it has a solution made up entirely of elementary functions. Elliptic functions may be involved.
 
I too struggled for it for 6-8 months. Its a kind of elliptic integral(which i didn't knew). u might be knowing. u can check it on an integrator at www.wolfram.com
 
Gosh - what a great tip. I didn't know the integrator existed. Thank you.

Having got the answer from Wolfram I'm kind of pleased that I hadn't missed an obvious solution.

Thank you all.
 

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