Simple differentition

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SUMMARY

The discussion focuses on using the limiting chord process to find the gradient of the curve defined by the function y = x² + 2 at the specific point (1, 3). The gradient is calculated using the formula lim_{h→0} (f(1+h) - f(1)) / h, where f(x) = x² + 2. Participants clarify that substituting points directly into the equation does not yield the required form for applying the gradient formula.

PREREQUISITES
  • Understanding of the limiting chord process in calculus
  • Familiarity with the concept of gradients and derivatives
  • Knowledge of polynomial functions, specifically quadratic functions
  • Basic algebra skills for manipulating equations
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  • Study the application of the limiting chord process in various functions
  • Learn about the formal definition of derivatives in calculus
  • Explore the relationship between limits and continuity in functions
  • Practice finding gradients of different polynomial curves using similar methods
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Students studying calculus, educators teaching differentiation techniques, and anyone seeking to understand the application of the limiting chord process in finding gradients of curves.

wellY--3
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hi,

I understand how to use the limiting chord process to find the gradient of a curve, but how do you do it when they ask for a certain point on the curve. for example

find the gradient using the limiting chord process on the curve y=x^2 +2 at the point (1,3)

If you sub the points into the equation it's no longer y= which you need to be able to use the formula they're wanting
 
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Nothing to do with differential equations! I am moving this to "Calculus and Analysis".

"find the gradient using the limiting chord process on the curve y=x^2 +2 at the point (1,3)."

The gradient is given by
[tex]\lim_{h\rightarrow 0}\frac{f(1+h)-f(1)}{h}[/tex]

With f(x)= x2+ 2, what is f(1)? What is f(1+h)?
 

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