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Simple differentition

  1. May 24, 2007 #1
    hi,

    I understand how to use the limiting chord process to find the gradient of a curve, but how do you do it when they ask for a certain point on the curve. for example

    find the gradient using the limiting chord process on the curve y=x^2 +2 at the point (1,3)

    If you sub the points into the equation it's no longer y= which you need to be able to use the formula they're wanting
     
  2. jcsd
  3. Jun 2, 2007 #2

    HallsofIvy

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    Nothing to do with differential equations! I am moving this to "Calculus and Analysis".

    "find the gradient using the limiting chord process on the curve y=x^2 +2 at the point (1,3)."

    The gradient is given by
    [tex]\lim_{h\rightarrow 0}\frac{f(1+h)-f(1)}{h}[/tex]

    With f(x)= x2+ 2, what is f(1)? What is f(1+h)?
     
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