Simple energy dissipated problem but I can't figure it out

  • Thread starter Thread starter jauser
  • Start date Start date
  • Tags Tags
    Energy Figure
Click For Summary

Homework Help Overview

The problem involves calculating the energy dissipated by a lamp when a current of 0.3A is passed through it for 2 minutes using a 6V power supply. The original poster attempts to use the power formula P=VI to find the energy but arrives at an incorrect value.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between power, energy, and time, with the original poster questioning their calculation of energy based on power and time. There is an emphasis on the importance of unit consistency in calculations.

Discussion Status

Some guidance has been offered regarding the correct approach to calculating energy using the relationship between power and time. Participants are exploring the implications of unit management in their calculations.

Contextual Notes

The original poster expresses uncertainty about their calculations and seeks clarification on the correct method to arrive at the expected energy value. There is a mention of the importance of carrying units through calculations to avoid errors.

jauser
Messages
6
Reaction score
0
Hi, I'm new, if I forgot something in asking my question the RIGHT way please direct me to the correct way.

Homework Statement


A current of 0.3A is passed through a lamp for 2 minutes using a 6V power supply. The energy dissipated by this lamp during the 2 minutes is:

Homework Equations


P=VI?

The Attempt at a Solution


So I took V*I=1.8W for Power
And took 1.8W dividing 120s to get 0.015J

BUT the correct answer is 216J, I don't know how that is. Please help, thanks.
 
Physics news on Phys.org
jauser said:
Hi, I'm new, if I forgot something in asking my question the RIGHT way please direct me to the correct way.

Homework Statement


A current of 0.3A is passed through a lamp for 2 minutes using a 6V power supply. The energy dissipated by this lamp during the 2 minutes is:

Homework Equations


P=VI?

The Attempt at a Solution


So I took V*I=1.8W for Power
And took 1.8W dividing 120s to get 0.015J

BUT the correct answer is 216J, I don't know how that is. Please help, thanks.

Welcome to the PF.

Energy is Power * Time. You have the correct equation for power; just fix what you did for the Energy calculation.

BTW, it's best to carry units along in your equations. That way you would have seen that the units weren't coming our right for Joules, and could have seen what you needed to do differently to get Energy units in the answer... :smile:
 
oh. That was simple. Thanks for the quick reply.

Love, =].
 
BTW, this page shows you how units like Watts and Joules are made up of the fundamental SI units. You can put these fundamental units in your equations whenever you want to check your work:

http://physics.nist.gov/cuu/Units/units.html

.
 
sweet, that'll be very helpful, the Units definitely always mess up my work
 
jauser said:
sweet, that'll be very helpful, the Units definitely always mess up my work

That was one of the most valuable lessons that I learned early in my undergrad. Get used to carrying units along in your equations, and cancel them out as appropriate just like you do variables (like meters/meters = 1). It helps your intuition about what variables go where (like velocity[m/s] = distance[m]/time), and helps you to catch errors early in equation manipulations.
 

Similar threads

Replies
4
Views
5K
  • · Replies 20 ·
Replies
20
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
1
Views
2K
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
13K
Replies
6
Views
9K