Simple equation involving natural log

[jsphgllwy]

Can anybody solve for x?



6=(36/9)ln(120/x)



The answer is x=22.3

I have so far got:

6=4*ln(120)-ln(x)
6=19.15-ln(x)

I think it may be incorrect

 

[Doc Al]

Hint:

$$e^{ln (x)} = \; ?$$