Factoring 28s^2 + 8st - 20t^2: A Simplified Explanation and Solution

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The discussion focuses on factoring the quadratic expression 28s^2 + 8st - 20t^2. The correct factorization is identified as 4(7s - 5t)(s + t). Participants suggest combining terms to simplify the expression, leading to a clearer path to the solution. The original poster expresses relief upon realizing the mistake and appreciates the help received. The interaction highlights the importance of careful term management in polynomial factorization.
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Homework Statement



28s^2 + 8st - 20t^2

The answer in the back of the book is 4(7s - 5t)(s + t)

2. The attempt at a solution

4(7s^2 + st + st - 5t^2)
4(7s^2 + st + st - 20t^2)
4(s(7s + t) + t(s - 20t))

I'm lost, can someone please help me?

Thanks in advance.
 
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In your first attempt at the solution, why not combine the second and third terms inside the (), it might make things more obvious.
 
Is there some trick to this that I am missing?

4(7s^2 + 2st - 5t^2)
 
Well, you could note that 2st=7st-5st, which makes your expression 4(7s2+7st-5st-5t2). Is this any easier to factorise?
 
OHH OHH OHHHH OHHHHHH!

Oh my god, how could I be so blind? That t^2 at the end threw me off. I feel like such an idiot. Thanks a billion cristo and robb, and I apologize for wasting your time :)
 

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