A player hits a volleyball when it is 4 ft above the ground with an initial vertical velocity of 20 ft/s (equation would be h = -16t2 + 20t + 4). What is the maximum height of the ball?
The Attempt at a Solution
t = -20 ±√202 - 4(-16)(4) / 2(-16)
t = -0.175390 and 1.425390
I don't think my answer is correct, but I don't know what else to do. And I don't know how to find the maximum height of the ball using the answer above :( Any help would be greatly appreciated, thank you!!