Simple fixed axis rotational problem

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Homework Help Overview

The problem involves a uniform stick pivoted at one end, released from a horizontal position, and requires finding the force exerted by the pivot immediately after release. The subject area includes rotational dynamics and torque analysis.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the force exerted by the pivot after release, having already found the angular acceleration. Some participants discuss the relationship between angular acceleration and the torque produced by gravity, while others question the choice of the axis of rotation for calculating moment of inertia and net torque.

Discussion Status

The discussion has progressed with participants exploring different aspects of torque and moment of inertia. A participant successfully calculated the force exerted by the pivot after considering the net torque and its relation to the pivot's position. There is an acknowledgment of the correct approach, but no explicit consensus on the overall method has been reached.

Contextual Notes

Participants are navigating the implications of using different axes of rotation for calculating torque and moment of inertia, which may affect their understanding of the problem. The original poster expresses uncertainty about the next steps in the problem-solving process.

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Homework Statement
A uniform stick of mass M = 2.1 kg and length L = 1.3 m is pivoted at one end. It is held horizontally and released. Assume the pivot is frictionless. Find the magnitude in Newtons of the force Fo exerted on the stick by the pivot immediately after it is released.

I calculated the angular acceleration immediately after the stick's release to be 11.3 rad/s^2 for another step of the problem (and that was the correct solution for that part of the problem), but other than that I don't really know where to begin this problem. Could someone just provide a hint as to the direction I should be going in?
 

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Running this through my head..., keeping in mind you have alpha, I would next think about what is causing that alpha.
 
Not entirely sure what you mean.

Gravity acts on the mass producing a torque of 13.368 Nm (from \alpha \frac{1}{3}ML^2 = \tau)...but I don't know where to go with that...
 
You specify a moment of inertia, this depends upon where the axis of rotation is taken. This can be used to calculate the net torque, again with a specific axis of rotation in mind.
 
Ah, thanks. I got 5.14, which was correct, by taking the net torque with an axis at the center of the stick. This allowed me to get the torque provided by the pivot by dividing the 13.368 Nm from my previous post by two. The result could then be divided by L=1.3 to get the force.

Thanks again for your help.
 
nice job !
 

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