A rectangular window in a house has dimensions 3.20 m x 2.40 m. As a storm passes by, the air pressure outside drops to 0.948 atm while the pressure inside the house remains 1.00 atm. What is the magnitude of the net force pushing on the window?
Take atmospheric pressure to be 101 kPa
Area of rectangle= 2(length + width)
1 atm = 101 kPa
The Attempt at a Solution
A = 2(3.2+2.4)= 11.2 m^3
P= 101 kPa (it only requires pressure inside house because that's the force of interest)
11.2* 101 kPa
what am i doing wrong? is it the units?