Simple Gravity Problem: Finding an Object's Maximum Height

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SUMMARY

The discussion centers on calculating the time it takes for an object to reach its maximum height when thrown straight up, given that it rises 80 meters and the acceleration due to gravity is 10 m/s². The correct approach involves using the kinematic equation for vertical motion, specifically \( t = \frac{v}{g} \), where \( v \) is the initial velocity. The maximum height is reached at half the total time of flight, leading to a time of 4 seconds to reach the maximum height, not 8 seconds as initially suggested.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of gravitational acceleration (g = 10 m/s²)
  • Ability to interpret motion graphs
  • Familiarity with the concept of maximum height in projectile motion
NEXT STEPS
  • Review kinematic equations for vertical motion
  • Study the concept of maximum height in projectile motion
  • Learn how to graph projectile motion and interpret motion graphs
  • Practice problems involving time of flight and maximum height calculations
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of projectile motion and kinematics.

mwhowell
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Homework Statement



An object is thrown strait up. It rises 80m and falls back to its original height. Take the object's original height as the origin and use g=10m/s^2.

How long does it take the object to reach its max height?


Homework Equations





The Attempt at a Solution



I learned this in physics 1 and I feel destroying my dorm room because I know how to do this but I am having a complete mental block and can't seem to do anything with this. I am getting 8s but that can't be right because it does not fit on the graph I need to graph the problem on.
 
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Are you sure you're solving only for the max height? Or did you solve for the time the object returned to its original height?
 

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