Simple harmonic motion and buoyant force

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Homework Help Overview

The problem involves a cylindrical wooden log loaded with lead, floating upright in water and set into vertical oscillation. The discussion focuses on demonstrating that the oscillation is simple harmonic and finding the period of oscillation while neglecting the damping effect of water.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the forces acting on the log in different positions (raised and submerged) and attempt to set up equations of motion based on the balance of buoyant force and weight. There are questions about the missing cross-sectional area and density of the log, as well as considerations of pressure differences.

Discussion Status

Some participants have provided insights into the relationship between buoyant force and weight, suggesting expressions for buoyant force in terms of water density and the submerged volume. Others are exploring the concept of restoring force and displacement from equilibrium, indicating a productive direction without reaching a consensus.

Contextual Notes

Participants note the absence of specific values for the cross-sectional area and the density of the log, which may affect the ability to proceed with calculations. The problem constraints also include neglecting the damping effect of water.

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Homework Statement



A cylindrical wooden log is loaded with lead at one end so that it floats upright in water. The length of the submerged portion is L = 2.56m. The log is set into vertical oscillation.
(a) Show that the oscillation is simple harmonic
(b) Find the period of oscillation

Neglect dampening effect by water

Homework Equations


The Attempt at a Solution



So I drew three pictures, one of the log in equilibrium, one with the log slightly raised, and one with the log slightly more submerged.

Case 2: Slightly Raised

[tex]F_b < W[/tex]

[tex]F_net = F_b - W = -m*a[/tex]

[tex]\rho_w * (A*L - A*\Delta y) * g - m*g = -m*\frac{dy^2}{dt^s}[/tex]

and, if this is correct, I'm not given the cross sectional area A or the density of the log, so not sure where to go.

Case 3: Slightly Pushed Down

[tex]F_b > W[/tex]

[tex]F_net = F_b - W = m*a[/tex]

[tex]\rho_w * (A*L + A*\Delta y) * g - m*g = m*\frac{dy^2}{dt^s}[/tex]

Same problem as case 2.

Some insight on where to go next would be nice :D

I'm thinking maybe trying to find the pressure differences at each delta y, but I'm sure there is a simpler way than that?

Thanks
 
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Any clues?
 
One knows W = mg, where m is the mass of the log.

At the equilibrium point, Fb = W. What is the expression for Fb in terms of ρ, where ρ = density of water, and L.

Let [itex]\xi[/itex] be the displacement from equilibrium, so one must be concerned about [tex]\ddot{\xi}[/tex].

Think about the restoring force per unit length.
 
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Astronuc said:
One knows W = mg, where m is the mass of the log.

At the equilibrium point, Fb = W. What is the expression for Fb in terms of ρ, where ρ = density of water, and L.

At equilibrium, we have Fb = W = Weight of displaced water = ρw * g * V = ρw * g * L * A

Where L * A is the length times the cross sectional area - but I am not given A, but that is a volume in terms of L?
 
Last edited:

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