- #1

phymath7

- 48

- 4

- TL;DR Summary
- In my physics lab,while mesuring the spring constant of a spiral spring,we were instructed to vibrate it in such a way that it only oscillates vertically.That means,suppose the spring vibrates along the 'y' axis,so it can't have any x or z component of oscillation.In simple term,it can't form a coupled harmonic osccilator system.

Same instruction was given while finding value of 'g' by a bar pendulum.

In the former case,does the spring obeys hooke's law while it forms a coupled harmonic oscillator system?Does the bar pendulum somehow breaks the simple harmonic motion(such that we can't apply the law for sumple harmonic motion)?

In the former case,does the spring obeys hooke's law while it forms a coupled harmonic oscillator system?Does the bar pendulum somehow breaks the simple harmonic motion(such that we can't apply the law for sumple harmonic motion)?