Simple harmonic motion and frequency; answer disagrees from answer key

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SUMMARY

The discussion centers on a physics problem involving simple harmonic motion of a block attached to a spring, oscillating between x = 10 cm and x = 50 cm with a period of 0.25 seconds. The correct amplitude is calculated as 20 cm, while the frequency is determined to be 4 Hz, contradicting the user's initial calculation of 2 Hz. The user misinterpreted the period by assuming it took 0.5 seconds to complete a full cycle, while the correct interpretation is that 0.25 seconds represents the time for half a cycle, leading to the correct frequency of 4 Hz as stated in option B of the answer choices.

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Homework Statement



A block attached to a spring oscillates in simple harmonic motion along the x axis. The limits of its motion are x = 10 cm and x = 50 cm and it goes from one of these extremes to the other in 0.25 s. Its amplitude and frequency are:

A) 40 cm, 2 Hz
B) 20 cm, 4 Hz
C) 40 cm, 2 Hz
D) 25 cm, 4 Hz
E) 20 cm, 2 Hz


Homework Equations



[tex]T = 1/f[/tex]

The Attempt at a Solution



I got the amplitude correct by adding the limits and dividing by two to find the midpoint of the motion, which was 30 cm, which I took to be equilibrium. Then I subtracted 10 cm, one limit of motion, from 30 cm, equilibrium to get the amplitude of 20 cm.

The frequency is where I mess up. I multiplied .25s by 2, since I thought it takes .25 seconds to complete half the cycle; I thought it must go back to the same extreme to complete a cycle, and thus would take another .25s. I got .5s for the period and then took the reciprocal of .5 for a frequency of 2 Hz.

The answer key however says the answer is B, a frequency of 4 Hz. Is this a mistake of the answer key or on my part? I do not see why the frequency would be 4.
 
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I'd say that you are correct and the answer key is wrong.
 

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