Simple Harmonic Motion find Mass

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SUMMARY

The discussion focuses on calculating the mass of a block undergoing Simple Harmonic Motion (SHM) attached to a spring with a spring constant (k) of 75 N/m and an amplitude of 0.15 m. The block's speed is given as 1.7 m/s when its displacement is 0.12 m from equilibrium. Using the energy conservation equations, the calculated mass is 0.21 kg, but the expected answer is 0.27 kg, indicating a discrepancy in the calculations or assumptions made during the problem-solving process.

PREREQUISITES
  • Understanding of Simple Harmonic Motion (SHM)
  • Familiarity with energy conservation principles in mechanics
  • Knowledge of spring constant (k) and its role in SHM
  • Ability to apply kinetic and potential energy formulas: E_k and E_s
NEXT STEPS
  • Review the derivation of energy conservation in Simple Harmonic Motion
  • Study the relationship between amplitude, displacement, and velocity in SHM
  • Explore the implications of mass calculations in oscillatory systems
  • Investigate potential sources of error in experimental measurements of mass
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to clarify concepts related to Simple Harmonic Motion and energy conservation.

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Homework Statement


A block is attached to a horizontal spring with k = 75 N/m undergoes SHM with an amplitude of 0.15m. If the speed of the block is 1.7 m/s when the displacement is 0.12m from equilibrium, what is the mass of the block?

Homework Equations


E = E'
E[itex]_{k}[/itex] = [itex]\frac{1}{2}[/itex]mv[itex]^{2}[/itex]
E[itex]_{s}[/itex] = [itex]\frac{1}{2}[/itex]kx[itex]^{2}[/itex]

The Attempt at a Solution


E = E'
E[itex]_{k1}[/itex] + E[itex]_{s1}[/itex] = E[itex]_{s2}[/itex]
[itex]\frac{1}{2}[/itex]mv[itex]^{2}[/itex] + [itex]\frac{1}{2}[/itex]kx[itex]^{2}[/itex] = [itex]\frac{1}{2}[/itex]kx[itex]^{2}[/itex]
Where subscript 1 indicates that x = 0.12 m and subscript 2 indicates that x = 0.15 m (max energy)
Substituting in ...
m = 0.21 kg

but the answer is 0.27 kg?
 
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With that data, the answer is m = 0.21 kg.
 

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