Simple Harmonic Motion Lab: Mass and Period Relationship Analysis

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Homework Help Overview

The discussion revolves around a physics lab focused on Simple Harmonic Motion, specifically analyzing the relationship between mass and the period of oscillation using experimental data collected from a spring-mass system.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive the relationship between mass and period using their collected data and the equation T=2π√(m/k). Some participants suggest plotting T² against mass to find the gradient, while others seek clarification on the implications of the gradient.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the relationship between mass and period. Some guidance has been offered regarding graphing techniques, but there is no explicit consensus on the approach to take.

Contextual Notes

Participants note that the teacher indicated the need for an equation relating period to mass rather than strictly deriving the period equation. This may influence the direction of the analysis.

turnerdhr
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Homework Statement


Hi
I just did a physics lab that involved a Simple Harmonic Motion. What I did was have a mass hung on a spring and then put different masses and find their Period (T) and time for 5 cycles going up and down.

RESULTS:

Mass (kg)
0.100
0.150
0.200
0.250
0.300


Time (s) for 5 cycles
2.12
2.36
2.67
3.01
3.35


Period (T)
0.424
0.472
0.53
0.60
0.67



X (meters)
0.04
0.05
0.07
0.95
0.115



So my question is how can i use my data that i collected to get the relation ship between the mass and period and also get the equation close to
T= 2pie * squareroot m/k

Any help Would be apperciated. Thank You for your time.




Homework Equations



T= 2pie * squareroot m/k



The Attempt at a Solution


Before I could get started i had to find my spring constant (k) which i did by putting a 0.2 kg mass and since Fg=Fx I did Fg=mg
=(0.2)(9.8)
= 1.96 N


So Since i knew my total Fx=1.96 N i measured my spring without the mass and got 0.07m as a measurement. So Fx=kx
1.96=0.07k
1.96/0.07=k
k=28 N/m

So I managed to figure out my constant on my spring.
I then started the lab and put different masses and timed the spring go vertically for 5 periods.
 
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So you know that T=2π√(m/k), so if you square both sides and then plot a graph of T2 vs. m, what would the gradient of that line be equal to?
 
not really sure what you mean by " gradient of that line be equal to? "

thanks for replying
 
turnerdhr said:
not really sure what you mean by " gradient of that line be equal to? "

thanks for replying

Square both sides of the equation and then put it in the form Y=MX+C. M will be the gradient.
 
okay so the slope, again thank you but when i asked my teacher she said you don't have to get exactly the period equation you just have to get and equation fo period vs mass, which i did on winplot.

thank you
 

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