Simple Harmonic Motion of a mass hanger

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SUMMARY

The discussion focuses on calculating the spring constant (k) of a spring using the principles of Simple Harmonic Motion. A 50 g mass hanger is initially motionless, and when a 91 g mass is added, the spring stretches by 7 cm. The relevant equations include F = k(ΔL) - mg and k(ΔLₑ) = mg, where g is given as 9.79 m/s². The challenge lies in determining the equilibrium position to find the displacement (y) for accurate calculation of k.

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Homework Statement


A 50 g mass hanger hangs moitionless from a partially stretched spring. When a 91 gram mass is added to the hanger, the spring stretch increases by 7 cm. What is the spring constant of the spring (in N/m)? (Assume g = 9.79 m/s2.)


Homework Equations


F=k(delta)L-mg
k(delta)L(sub_e)=mg
(delta)L=(delta)L(sub_e)-y

The Attempt at a Solution


I tried to use the three formulas above to solve for k, however; since I don't know the equilibrium position, I can't find y, which is the displacement of the mass from the equilibrium position.
 
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