Simple harmonic motion of a spring

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SUMMARY

The discussion focuses on calculating the angular frequency of a horizontal plank attached to a spring for small oscillations. The plank has a mass of 2.0 kg and a length of 1.0 m, with the spring constant set at 1.0 x 103 N/m. The relevant formula for angular frequency is derived from the equation w = (mgd/I)0.5, where I is the moment of inertia calculated as I = (1/3)ML2. The solution involves substituting the values into the formula to find the angular frequency in radians per second.

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myoplex11
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Homework Statement


A horizontal plank (m = 2.0 kg, L = 1.0 m) is pivoted at one end. A spring
(k = 1.0 x 10
3
N/m) is attached at the other end, as shown in the figure. Find the angular frequency
(in rad/s) for small oscillations


Homework Equations



w = (mgd/I)^0.5 I= 1/3 ML^2

The Attempt at a Solution


w = (2*9.8*1/ (2/3)
 
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I'm not sure what you did here. Start by writing the force equation and comparing it to that for a simple mass on a spring.
 
myoplex11 said:

Homework Statement


A horizontal plank (m = 2.0 kg, L = 1.0 m) is pivoted at one end. A spring
(k = 1.0 x 10
3
N/m) is attached at the other end, as shown in the figure. Find the angular frequency
(in rad/s) for small oscillations

Hi myoplex11, Please don't post the same thing more than once.
 

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