Simple Harmonic Motion - position

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SUMMARY

The discussion focuses on a physics problem involving simple harmonic motion (SHM) of a 100 g ball attached to a spring with a spring constant of 2.9 N/m. The ball's maximum acceleration is calculated to be 180 cm/s² when its position is 4.8 cm and its velocity is 20 cm/s. The equations used include x(t) = Acos(ωt) and x(t) = Acos(2πft), which are fundamental to understanding SHM. The key question raised is determining the time at which the acceleration reaches its maximum value.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM)
  • Familiarity with spring constants and mass calculations
  • Knowledge of the equations of motion for SHM
  • Basic principles of oscillatory motion and acceleration
NEXT STEPS
  • Study the derivation of maximum acceleration in simple harmonic motion
  • Learn how to calculate angular frequency (ω) in SHM
  • Explore the relationship between position, velocity, and acceleration in oscillatory systems
  • Investigate the effects of varying spring constants on oscillation characteristics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to enhance their understanding of simple harmonic motion concepts.

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Homework Statement



A 100 g ball attached to a spring with spring constant 2.9 oscillates horizontally on a frictionless table. Its velocity is 20 cm/s when x = 4.8 cm.

What is the ball's maximum acceleration?
which I found to be amax= 180 cm/s^2

What is the ball's position when the acceleration is maximum?

Homework Equations



x(t)= Acos(ωt)
x(t)= Acos(2pift)

The Attempt at a Solution


 
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Well at what time t is the acceleration maximum?
 

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