# Simple kinematics question i think i am right just need to confirm

1. Aug 29, 2010

### ihatecats2014

1. The problem statement, all variables and given/known data
At t=0 a ball, initially at rest, starts to roll down a ramp with constant acceleration. You notice it moves 1 foot between t=0 seconds and t = 1 second.
How far does it move between t = 1 second and t = 2 seconds

2. Relevant equations
delta x=vit+1/2at2? since it is constant speed wouldn't acceleration be 0?

3. The attempt at a solution
it seems like it would be 1 foot right?
= 1(1)+1/2(0)(1)2
delta x=1foot?

2. Aug 29, 2010

### rock.freak667

No the acceleration would not be zero. If it were zero, then the ball would not move.

Using this information and the same relevant equations, what is the acceleration? (Remember, initially at rest means no initial velocity)

3. Aug 29, 2010

### ihatecats2014

would the acceleration be 1? because it went 1 foot in the elapsed time of 1 sec?

then
=0(1)+1/2(1)(1)^2
delta x equals 1/2 foot
this is wrong. i need a hint please

or if the time is 2sec the distance would then be 2 foot. but i think that is still wrong

4. Aug 29, 2010

### rock.freak667

Your equation is x=ut+0.5at2 (u= initial velocity)

Using this equation a≠1 ft/s2.