Simple NonHomogenous Differential Equation Question

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SUMMARY

The discussion centers on solving the non-homogeneous differential equation y''' - 9y'' + 18y' = 30e^x. The participant correctly factored the characteristic equation to find roots r = 0, r = 3, and r = 6, leading to the general solution y(x) = C0 + C1e^(3x) + C2e^(6x). The particular solution was determined as yp = 3e^x, resulting in the complete solution y(x) = C0 + C1e^(3x) + C2e^(6x) + 3e^x. The participant confirmed the correctness of their approach by suggesting substitution back into the original differential equation.

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  • Understanding of non-homogeneous differential equations
  • Familiarity with characteristic equations and their roots
  • Knowledge of particular solutions in differential equations
  • Ability to perform substitution to verify solutions
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Homework Statement


y"' -9y" +18y" = 30ex. Does not matter what the initial conditions are for my question.


Homework Equations


N/A


The Attempt at a Solution


So I factored out the equation and got:
r*(r2 - 9r + 18)
Which gives roots r = 0, r = 3, r = 6.
Which gives me the general solution:
y(x) = C0*1 + C1e3x + C2e6x
Is the above general solution correct?
Next question I have is whether I solved for the yp correctly.
yp = A*ex
yp' = A*ex
yp" = A*ex
yp'" = A*ex
which by plugging into the equation will give.
A*ex - 9A*ex + 18A*ex = 30ex
which gives 10A*ex = 30ex
which gives A = 3.
Which means my general solution should be.
y(x) = y(x) = C0*1 + C1e3x + C2e6x +3*ex
Is all this correct because I am trying to solve for the "C0, C1, etc." and I want to be absolutely sure that the base I am working with is correct and that my error is just a miscalculation with the initial conditions. Thanks.
 
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At first glance it looks OK to me. But if you really want to be sure, all you have to do is substitute your general solution back into the DE and see if it works.
 
Hmm didn't think about substituting back into the original DE. Thanks a lot for the tip.
 

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