Simple(?) parabolic dish design question

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The discussion revolves around designing a parabolic optical mirror with specific parameters for diameter (D) and focal length (f), where f is defined as a perpendicular distance from D. The user, Joe, is struggling with self-referential calculations to derive the necessary dimensions. He eventually arrives at a solution involving the relationship between the radius of the dish, the distance from the front edge to the focus, and the parameter 'a' of the parabola equation. The final equations relate the focal length, depth, and dimensions of the dish, allowing for a general solution to the design problem. This exploration highlights the complexities of parabolic mirror design and the mathematical relationships involved.
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TL;DR
Not feeling too good, slowing me down a bit :).
I want to use this to design a parabolic (optical) mirror;

Capture.GIF

The problem is that in my application I need both D and f to be a parameter, but I need to specify f only as a perpendicular distance from D. In other words, I need to specify some f_2=f-d, and calculate d. I can't seem to come up with a way to do this without self-reference.

Thanks so much

Joe

ETA N/M it just took me an extra second. I'll post the solution shortly

ETA II Nope, sorry, still self reference problems. It's so annoying cause it seems so simple :/

ETA III Maple CAS says it's
Capture.GIF

(where f=f_2)but I'll be durned if I know how it got there.
 
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Specify the distance from front edge of dish to focus as g.
Then; f = d + g; d = f - g;
You specify the paraboloid size by radius; r = diameter / 2.
Given r and g, solve for parameter a of the parabola equation.
y = a * x^2

The slope of surface is; y' = 2*a*x
When 45°, slope = 1, y = f
1 = 2 * a * x
x = 1 / ( 2 * a )
f = y = a / ( 4*a^2 )
f = 1 / ( 4 * a )
For the rim of the dish.
d = a * r^2
f - g = a * r^2
f = g + ( a * r^2 )
equate the two equations for f.
g + ( a * r^2 ) = 1 / ( 4 * a )
( r^2 * a^2 ) + (g * a) - 1/4 = 0
Then solve that quadratic for the parameter a.
 
I think this is a general solution.
Specify radius of dish; r = diam / 2
Specify distance from front face of dish to focus; g
Vertex is at the origin so surface eqn; y = a · x²
Temporary; t = √ ( r² + g² ) ; which is distance from focus to lip
Parameter; a = ( t - g ) / ( 2 · r² )
Position of focus on y axis; f = 1 / ( 4 · a )
Depth of dish; d = f - g
 

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