Simple Pendelum - Help with Quadratic Regression on Excel?

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The discussion focuses on determining the gravitational constant (g) using a simple pendulum and quadratic regression in Excel. A scatter plot has been created with pendulum length (L) on the x-axis and period (P) on the y-axis, but the user struggles to find a single trend line that fits all series for different lengths. The small angle approximation equation, L = (G/((2π)^2)) P^2, is referenced, highlighting the relationship between length, gravity, and period. Concerns are raised about the accuracy of the regression results, suggesting that fitting a quadratic to a single series may not be necessary and that averaging measurements could be more effective. The discussion emphasizes the need for a more accurate method to analyze the data collectively.
kmr159
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1.
I am trying to determine the value of g based on a simple pendulum.
I have graphed a scatter plot with the x-axis as L and the y-axis as P. I have 3 different series for different lengths of pendulum. When I try to find a line of best fit I get something like cx^2 + dx + e and this trend line is only for one series.

2 Parts - Is there any way to get the trend line to be the line of best fit for all my different series (different lengths)
- Is there any way to make my quadratic regression approximate only in terms of ax^2.





2.
The equation, for a small angle approximation works out to L=(G/((2pi)^2)) P^2. Where L is the length of the Pendulum in meters, G is Gravity and P is the period of the pendulum.




3. excel graph - the regression gives a wildly incorrect value of G. Attempt: Determined the formula and how to get the solution
 
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One series consists of a set of measurements of the period, all with the same length? If so, why would you fit a quadratic to that? Why isn't it just a matter of taking the mean? Or, throw all the data into one chart, using an XY plot?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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