The coefficient of static friction between the m = 2.80 kg crate and the 35.0° incline of the figure below is 0.260. What minimum force must be applied to the crate perpendicular to the incline to prevent the crate from sliding down the incline?(adsbygoogle = window.adsbygoogle || []).push({});

Attached is a picture.

I broke down the mass into 27.44 weight, which is not perpendicular to the slope so I broke down the 27.44 into components of 15.75 facing perpendicular towards the slope, and 22.5 going down the slope.

coefficient of static friction is .260(N) N= 15.7 since it is opposite of the weight.

so coefficient ends up being 4.1. so its Force should equal atleast 4.1+22.5. which is 26.6.

the answer is 38.1.........what am I doing wrong here? Please help.

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# Homework Help: Simple Physics Problem (pushing a crate up a slope)

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