Finding Minimum Force Applied to Keep Objects Stationary?

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SUMMARY

The discussion focuses on calculating the minimum force required to keep a crate stationary on an incline with a coefficient of static friction of 0.300 and an angle of 35°. The relevant forces include the gravitational force component down the incline (mgsinθ) and the frictional force (μsmgcosθ). The correct equation to determine the applied force F is mgsinθ - μsmgcosθ + F = 0, emphasizing that the applied force contributes to the frictional force needed to prevent sliding.

PREREQUISITES
  • Understanding of static friction and its coefficient
  • Basic knowledge of forces acting on inclined planes
  • Familiarity with Newton's second law (f=ma)
  • Ability to perform trigonometric calculations involving angles
NEXT STEPS
  • Study the principles of static friction and its applications in physics
  • Learn how to resolve forces on inclined planes using free-body diagrams
  • Explore the relationship between applied forces and frictional forces in static scenarios
  • Investigate the effects of varying angles and coefficients of friction on force calculations
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Students in physics, engineers working on mechanical systems, and anyone interested in understanding the dynamics of forces on inclined surfaces.

morgane28v
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The coefficient of static friction between the crate m1=3.00kg and the incline with θ=35° shown in the figure below is .300. What minimum force F must be applied to the crate perpendicular to the incline to prevent the crate from sliding down the incline?


mgsinθ
μsmgcosθ
f=ma

I don't quite get how the applied force fits into the equation. mgsinθ-μsmgcosθ+F=0?
 

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Your equation is almost right. You are not interested so much in F itself but the additional frictional force caused by F.
 
Okay thank you I got it!
 

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