Simple Projectile Motion of ball

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SUMMARY

The discussion centers on calculating the initial speed of a ball thrown horizontally from a height of 58 meters, landing 35 meters away from the base of the building. The user initially misidentified the vertical and horizontal distances, leading to an incorrect calculation of the ball's speed. The correct vertical distance is 58 meters (Y=58m) and the horizontal distance is 35 meters (X=35m). The correct initial speed calculation yields a value of approximately 17.15 m/s.

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  • Understanding of basic physics concepts, specifically projectile motion
  • Familiarity with kinematic equations
  • Knowledge of gravitational acceleration (9.8 m/s²)
  • Ability to solve quadratic equations
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of projectile motion and solving related problems in mechanics.

RedBurns
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Can someone tell me what I'm doing wrong here:

A ball is thrown horizontally from the roof of a building 58 m tall and lands 35 m from the base. What was the ball's initial speed?

X0= 0m Y0= 0m
X= 58 m Y= 35 m
Vx=? Vy=0 m/s
Ax=0 m/s/s Ax=-9.8 m/s/s
T=?

35=0+0T-.5(-9.8)T^2
T=2.6 s

58=0+Vx(2.6)
Vx= 22 m/s <----------I know this is wrong
 
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RedBurns said:
Can someone tell me what I'm doing wrong here:

A ball is thrown horizontally from the roof of a building 58 m tall and lands 35 m from the base. What was the ball's initial speed?

X0= 0m Y0= 0m
X= 58 m Y= 35 m
Vx=? Vy=0 m/s
Ax=0 m/s/s Ax=-9.8 m/s/s
T=?

35=0+0T-.5(-9.8)T^2
T=2.6 s

58=0+Vx(2.6)
Vx= 22 m/s <----------I know this is wrong

You've got your distances reversed! The building is 58m tall- that's the vertical distance: Y= 58m. The ball went 35 m horizontally: X= 35m
 
Thanks! I should have known it was something like that after cheking my math so any times
 

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