- #1

- 2

- 0

1 / 0 = x, so x * 0 = 1

But 0 does not equal 1, so x / 0 is unsolvable.

Oh, and I'm new to forums so if this shouldn't be here you can delete it.

- Thread starter Poolala
- Start date

- #1

- 2

- 0

1 / 0 = x, so x * 0 = 1

But 0 does not equal 1, so x / 0 is unsolvable.

Oh, and I'm new to forums so if this shouldn't be here you can delete it.

- #2

- 95

- 2

Perhaps you want to look at:

[itex]\underbrace{lim}_{i->0} \frac{Sin(x)}{x} = 1[/itex]

[itex]\underbrace{lim}_{i->0} \frac{Sin(x)}{x} = 1[/itex]

- #3

Simon Bridge

Science Advisor

Homework Helper

- 17,857

- 1,655

$$\lim_{x\rightarrow 0}\frac{\sin(x)}{x}=1$$

... mathematicians can set up numbers to do all kinds of things.

- #4

Hurkyl

Staff Emeritus

Science Advisor

Gold Member

- 14,916

- 19

This argument makes the assumption that, whenever x/y is defined, the equation y(x/y) = x holds. It also makes the assumption that x0 is always defined, and it is 0.

1 / 0 = x, so x * 0 = 1

But 0 does not equal 1, so x / 0 is unsolvable.

Oh, and I'm new to forums so if this shouldn't be here you can delete it.

Both of these assumptions are, indeed, true for the real number system, and the complex number system. But other important number systems do not have these properties.

RamaWolf is talking about something different (although some people have trouble distinguishing the two).

- #5

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 961

Yes, that's a perfectly valid proof that the number 0 (or the additive identity in any field with more than one member) does not have an inverse.

1 / 0 = x, so x * 0 = 1

But 0 does not equal 1, so x / 0 is unsolvable.

Oh, and I'm new to forums so if this shouldn't be here you can delete it.

True but has nothing to do with the topic here.Perhaps you want to look at:

[itex]\underbrace{lim}_{i->0} \frac{Sin(x)}{x} = 1[/itex]

- #6

- 2

- 0

Oh, and I've been thinking: does 0 / 0 = 1, or is it undefined?

- #7

- 841

- 0

In most number systems 0/0 is undefined. Only a few exotic number systems have defined it and that is outside my scope.Oh, and I've been thinking: does 0 / 0 = 1, or is it undefined?

- Last Post

- Replies
- 39

- Views
- 13K

- Last Post

- Replies
- 18

- Views
- 12K

- Replies
- 2

- Views
- 7K

- Replies
- 2

- Views
- 2K

- Replies
- 7

- Views
- 9K

- Last Post

- Replies
- 1

- Views
- 517

- Last Post

- Replies
- 3

- Views
- 4K

- Last Post

- Replies
- 1

- Views
- 2K

- Last Post

- Replies
- 5

- Views
- 12K

- Last Post

- Replies
- 2

- Views
- 7K